Question

given sin A =6/10 find other ratios​

Answer 1

hey ..!!

given here

sin A =6/10

find here

cos A=?

tan A=?

cot A=?

cosec A=?

sec A=?

Solution :--

we know..

cos A =√[1-sin ²A]

so,

cos A= √[1-(6/10)²]

cos A=√[1-36/100)]

=√[(100-36)/100]

=√[64/100]

=8/10

=4/5

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sec A = 1/cos A

= 1/(4/5)

= 5/4

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tan A=sin A/cos A

=( 6/10)/(4/5)

= 6/10 × 5/4

= 3/5 × 5/4

= 3/4

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cot A = 1/tan A

= 1/(3/4)

= 4/3

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cosec A= 1/sin A

= 1/(6/10)

= 10/6

= 5/3

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