Question

Given, sin(A-B) = 1/2= cos(A+B), where 0<(A+B)< 90° and A > B​

Answer 1

Answer:

A=45 degree and B=15 degree

Answer 2

Answer:

sin(A-B) = 1/2

sin(A-B) = sin30°

A-B = 30° ----------(1)

cos(A+B) = 1/2

cos(A+B) = cos60°

A+B = 60° ----------(2)

Adding (1) and (2),

2A = 90°

A = 45° ----------(3)

Substituting (3) in (1),

45°-B = 30°

B = 15°

∴ ∠A = 45°

   ∠B = 15°

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