Question

given sinA=3/5find tanA cosA​

Answer 1

Answer:

this is the answer of your question

Answer 2

Answer:

sin =

$\frac{oposite \: to \: angle}{hypotnuse}$

given

opposite side of triangle = 3

hypotnuse = 5

the adjacent side of triangle is = 4 (by pythogaras thereom ssum of squares of two sides = hypotnuse square)

therefore

cosA =

$\frac{adjacent \: to \: angle}{hypotnuse}$

cosA =

$cos \: a \: = \frac{4}{5}$

tanA =

$tan \: a \: = \frac{opposite \: side \: to \: anle}{adjacent \: side \: of \: an \: angle}$

$tan \: a = \frac{3}{4}$

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