Question

Given sinA=8/10 Find all the angles trigonometry ratio ​

Answer 1

Answer:

sinA=8/10=p/h

now,

b^2= h^2-p^2

b^2= 10^2-8^2

b^2 = 100-64

b^2 = 36

b = √36

: . b= 6

here,

cosA= b/h= 6/10=3/5

cosecA=h/p=10/8=5/4

cotA= b/p = 6/8= 3/4

secA=h/b= 10/6=5/3

tanA= p/b = 8/6= 4/3