Question

given standard electrode potentials

Fe^3+ 3e ---> Fe E°= -0.036v
Fe^2+ 2e ----> Fe E°= -0.0440v

the standard electrode potential E° for fe^3+ +e ----> Fe^2+ is ​

Answer 1

Answer:

Fe³⁺ + e⁻ → Fe²⁺ ; E° = +0.77 V

Explanation:

Given:

Fe³⁺ + 3e⁻ → Fe ; E°₁ = -0.036v --------(i)

Fe²⁺ + 2e⁻ → Fe ; E°₂ = -0.440v -------(ii)

To find:

Fe³⁺ + e⁻ → Fe²⁺ ; E° = ? --------(iii)

Step-by-step solution:

We have, (i) - (ii) = (iii)

∴ ΔG°₁ - ΔG°₂ = ΔG°

⇒ -nFE°₁ - (-nFE°₂) = -nFE°    [n denotes the no. of electrons involved in the respective reactions]

⇒ 3 × (-0.036) - 2 × (-0.44) = 1 × E°

⇒ E° = +0.77 V

Answer 2

Answer:

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