Physics, asked by PhoenixPie, 4 months ago

Given standard electrode potentials:

K*/K=-293 V,
Ag / Ag=0.80 V,
Hg2+ / Hg = +0.79 V,
Mg2+ / Mg =-237 V,
Cr+Cr=-0.74 V.

Which acts as a better oxidizing agent?

(a) Mg2+

(b) G

(c) Ag

(d) K*​

Answers

Answered by nehaliganvit3
0

Explanation:

04.01.2018

Chemistry

Secondary School

answered • expert verified

Question 8.29 Given the standard electrode potentials,

K+/K = –2.93V, Ag+/Ag = 0.80V,

Hg2+/Hg = 0.79V

Mg2+/Mg = –2.37V. Cr3+/Cr = –0.74V

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