given tan 2a=2tana÷1-tan^2 a. if tan 30=1÷square root of 3,verify that tan 60=square root of 3
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Given that,
tan2A=2tanA/(1-tan²A)
and,
tan30=1/√3.........................1
Now,
LHS=tan60
=tan2(30)
=2tan30/(1-tan²30)
=[2(1/√3)]/[1-(1/√3)²] (by eq1)
=(2/√3)/[1-1/3]
=(2/√3)/[2/3]
=3/√3
=√3
=RHS
tan2A=2tanA/(1-tan²A)
and,
tan30=1/√3.........................1
Now,
LHS=tan60
=tan2(30)
=2tan30/(1-tan²30)
=[2(1/√3)]/[1-(1/√3)²] (by eq1)
=(2/√3)/[1-1/3]
=(2/√3)/[2/3]
=3/√3
=√3
=RHS
Maninder3281:
please tell me that why you put tan =60,???
it is a way of verifying
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