Question

given tan A = 4/3 find Sin A and COSA.​

Answer 1

P is perpendicular

B is base

H is hypotenuse

tanA = 4/3 = P/B

H² = P² + B²

H = √ (4)² + (3)²

H = √16 +9

H= √25

H =5

sinA = P/H

sinA = 4/5

cosA = B/H

cosA = 3/5

hope you get your answer