Question

given tan A =4/3, find the other trigonometric ratios of the angle A​

Answer 1

Step-by-step explanation:

tan A = 4(opp)/3(adj)

hyp²=4²+3²

=16+9

hyp=√25=5units.

sin A=opp/hyp=4/5

cos A = adj/hyp=3/5.

cosec A= 1/sinA=5/4

sec A=1/cos A=5/3

cot A=1/tanA =3/4.

Answer 2

Step-by-step explanation:

$\huge\underline{\underline{\ Question}}$

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$\tan(a) = \frac{4}{3} \\ find \: other \: trigo \: ratios \: of \: angle \: of \: (a)$

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$\huge\underline{\underline{\ Answer}}$

$\tan(a) = \frac{4}{3} \\ \huge \boxed{ \cot(a) = \frac{1}{ \tan(a) } } \\ \boxed{ \cot(a) = \frac{1}{ \tan(a) } = \frac{3}{4} } \\ \\ also \\ \huge\boxed{ { \tan}^{2}(a) + 1 = { \sec}^{2} (a)} \\ \frac{16}{9} + 1 = { \sec}^{2} (a) \\ { \sec}^{2}(a) = \frac{25}{9} \\ \boxed{ \sec(a) = \frac{5}{3} } \\ \\ \huge \boxed{ \cos(a) = \frac{1}{ \sec(a) }} \\ \cos(a) = ( \frac{1}{ \frac{5}{3} } ) \\ \boxed{ \cos(a) = \frac{3}{5} } \\ \\ \huge \boxed{ { \sin}^{2} (a) + { \cos}^{2} (a) = 1} \\ { \sin}^{2} (a) = 1 - \frac{9}{25} \\ { \sin}^{2} (a) = \frac{16}{25} \\ \boxed{ \sin(a) = \frac{4}{5} } \\ \\ \huge \boxed{ \sin(a) = \frac{1}{ \csc(a) } } \\ \csc(a) = \frac{1}{ \frac{4}{5} } \\ \boxed{ \csc(a) = \frac{5}{4} }$