Given tan a = 5/12 , find the other trigonometric ratios of the angle
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Answers
Answer:
tan a= Opp.side/Adj.side=5/12
In a right angle triangle,
(Opp.side)^2 + (Adj.side)^2= (Hypotenuse)^2
(5)^2 + (12)^2 = (Hypotenuse)^2
169= (Hypotenuse)^2
13= Hypotenuse
sinA=Opp.side/Hypotenuse
=5/13
cosA=Adj.side/Hypotenuse
=12/13
tan A=Opp.side/Adj.side (Given)
=5/12
secA=Hypotenuse/Adj.side
=13/12
cosecA=Hypotenuse/Opp.side
=13/5
cotA=Adj.side/Opp.side
=12/5
Answer:
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Step-by-step explanation:
tan A = 5/12 = Opposite side/ adjacent side
Assume a right angled triangle. Find the hypotenuse using the pythagoras theorem. Hypotenuse = √(144+25) = √169 = 13
Sin A = Opposite side / Hypotenuse = 5/13
Cosec A = 1/sin A =13/5
Cos A = Adjacent side / Hypotenuse = 12/13
sec A = 1/ cos A = 13/12
Cot A = 1/tan A =12/5