Given tan A = 5/12, find the values of sinA ,cosA, secA and cosecA
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Answered by
1
Step-by-step explanation:
tana=5/12
tan@=p/b
p=5,b=12,h=√25+144=13
SinA=p/h=5/13
cosA=b/h=12/13
seca=h/b=13/12
coseca=h/p=13/5
Answered by
0
Step-by-step explanation:
sin a=5/13
cos a=12/13
sec a=13/12
cosec a=12/5
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