Question

given tan a is equal to 4 / 3 find sin and Cos​

Answer 1

Refer to the attachment:

tanA = 4/3

BC/AB = 4/3 = K

BC = 4K , AB = 3K

By Pythagoras theorem:

AC² = AB² + BC²

=> AC = $\sqrt{(3k)^2 + (4k)^2}$

=> AC = $\sqrt{9k^2 + 16k^2}$

=> AC = $\sqrt{25k^2}$

=> AC = 5k

SinA = BC/AC = 4/5

CosA = AB/AC = 3/5

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