given tan a is equal to 4 upon 3 find cosec a upon Cos A minus sec a
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P=4
B=3
therefore,Hy=b by pythagoras theorum
cosecA=5/4
cotA=3/4
secA=5/3
cosecA/cotA=5/4 / 3/4
=5/4 * 4/3
=5/3
cosecA/cotA - secA = 5/3-5/3 = 0
B=3
therefore,Hy=b by pythagoras theorum
cosecA=5/4
cotA=3/4
secA=5/3
cosecA/cotA=5/4 / 3/4
=5/4 * 4/3
=5/3
cosecA/cotA - secA = 5/3-5/3 = 0
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