Question

Given : $2Br^- \rightarrow Br_2 + 2e^-$; E° = - 1.09 V;
$I_2 + 2e^- \rightarrow 2I^-$; E° = 0.54V
$Fe^{2+} + 2e \rightarrow Fe$; E° = - 0.44V
Which of the following reactions will not be spontaneous?
(a) $Fe + Br_2 \rightarrow FeBr_2$
(b) $Fe + I_2 \rightarrow FeI_2$
(c) $I_2 + 2Br^- \rightarrow 2I^- + Br_2$
(d) $Br_2 + 2I^- \rightarrow 2Br^- + I_2$

Answer 1

option d is the answer for the question

Answer 2

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$<b>$
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$\mathbb{NICE...QUESTION}$

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→ [B]


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