Chemistry, asked by amrik30101, 1 year ago

Given E^0_{Cr^{3+}/Cr} = –0.72 V, E^0_{Fe^{2+}/Fe} = –0.42 V. The potential for the cell Cr | Cr³⁺ (0.1M)|| Fe²⁺ (0.01 M)| Fe is (a) 0.26 V (b) 0.336 V(c) – 0.339 (d) 0.26 V

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Answered by InzilPinto7
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