Physics, asked by MohamedDanish3721, 1 year ago

Given F^{abc} = [P] F^{dq0}, where Park’s transformation \left[\begin{array}{ccc}k_d \cos \theta&k_q \sin \theta&k_0\\k_d\cos\lgroup \theta - \frac{2 \pi}{3} \rgroup &k_q \sin\lgroup \theta -\frac{2 \pi}{3} \rgroup &k_0\\k_d\cos\lgroup \theta + \frac{2 \pi}{3} \rgroup &k_q \sin\lgroup \theta +\frac{2 \pi}{3} \rgroup&k_0\end{array}\right] (where k_d = k_q=\sqrt{\frac{2}{3} } and k_0=\sqrt{\frac{1}{3} })

Answers

Answered by vivekpnair11479
0

WHAT DO WE HAVE TO FIND BRO????????????????

Answered by Anonymous
0

Ok so here is your answer mate:

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