Question

Given,
$\sqrt{2} + \sqrt[3]{2} + \sqrt[4]{2} + \sqrt[5]{2} ......$
Find:
i) Sum of nth term
ii) Sum upto 8th term

Answer 1

Answer:

Common difference is equal.

=> 3x + 6 - (2x + k) = 2x +k - x

=> 3x + 6 - 2x - k = x + k

=> x + 6 - k = x + k

=> 6 - k = k

=> 2k = 6

=> k=3

Answer 2

Answer:

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