Given,
![\sqrt{2} + \sqrt[3]{2} + \sqrt[4]{2} + \sqrt[5]{2} ......](https://tex.z-dn.net/?f=%5Csqrt%7B2%7D++%2B+%5Csqrt%5B3%5D%7B2%7D+%2B+%5Csqrt%5B4%5D%7B2%7D++%2B+%5Csqrt%5B5%5D%7B2%7D++...... "\sqrt{2} + \sqrt[3]{2} + \sqrt[4]{2} + \sqrt[5]{2} ......")
Find:
i) Sum of nth term
ii) Sum upto 8th term
Answers
Answered by
0
Answer:
Common difference is equal.
=> 3x + 6 - (2x + k) = 2x +k - x
=> 3x + 6 - 2x - k = x + k
=> x + 6 - k = x + k
=> 6 - k = k
=> 2k = 6
=> k=3
Answered by
0
Answer:
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