Given that 1 is a zero of the cubic polynomial 6^3-11x²-x+6, find its other zeros
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Answer:
Consider the given equation,
6x
3
−11x
2
+6x−1=0
Put,x=1 we get
6.1
3
−11.1
2
+6.1−1=0
0=0
Hence, x=1 ⇒x−1=0 is zeroes os given equation.
Now
x−1
)6x
3
−11x
2
+6x−1
6x
2
−5x+1
−(6x
3
−6x
2
)
−5x
2
+6x−1
−(−5x
2
+5x)
x−1
−(x−1)
0
Now,
6x
2
−5x+1=0
6x
2
−3x−2x+1=0
3x(2x−1)−(2x−1)=0
(2x−1)(3x−1)=0
So,
6x
3
−11x
2
+6x−1=(2x−1)(3x−1)(x−1)=0
Hence, x=1,
2
1
,
3
1
in H.P.
Hence, this is the answer.
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