Question

Given that 10g of a dibasic acid (molar mass=100) are present in 600 mL of the solution. The density of the solution is 1.02 g/mL. Molality of solution is

Answer 1

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Answer 2

Answer: The molality of solution is 0.17 mole/kg.

Explanation:

Molality : It is defined as the number of moles of solute present per kg of solvent

Formula used :

$Molality=\frac{n\times 1000}{W_s}$

where,

n= moles of solute

$Moles=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{10g}{100g/mol}=0.1moles$  

$W_s$ = weight of solvent in g

Given: Volume of solution = 600 ml

Density of solution = 1.02 g/ml

Mass of solution=$Density\times Volume=1.02\times 600=612g$

Mass of solute = 10 g

Thus mass of solvent = (612-10) g= 602 g

$Molality=\frac{0.1\times 1000}{602}=0.17mol/kg$

Therefore, the molality of solution will be 0.17 mole/kg.