Question

Given that √2 is a zero of the polynomial p(x) = 6x^3 + √2x^2- 10x - 4√2, find all the zeroes

Answer 1

Answer:

other roots are -2 root 2/3 and - root 2/2

Step-by-step explanation:

hope it helps you

Answer 2

Answer:

If

$\alpha = \sqrt{2}$

Then after solving the values

$\alpha + \beta + \gamma = \frac{ - \sqrt{2} }{6}$

Then

$\beta + \gamma = \frac{ - \sqrt{2} }{3}$

And

$\alpha \beta \gamma = \frac{4 \sqrt{2} }{6} = \frac{2 \sqrt{2} }{3}$

Then

$\beta \gamma = \frac{2}{3}$

Now find

${ \beta }^{2} + { \gamma }^{2} = \frac{ - 10}{9}$

From this u can find the value of

$\beta - \gamma =$

And solve the eqns then u can get the values

$\beta = \frac{ - \sqrt{2} + 4i}{3}$

$\gamma = \frac{ - \sqrt{2} - 4i}{3}$