Given that √2 is irrational number. Prove that (5+3√2) is an irrational number.
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Step-by-step explanation:
Let us assume that5+3√2is an rational number
5+3√2=p/q(where p and q are coprime integers and q not equal to 0)
3√2=p-5
√2=(p-5)/3
We know that √2 is irrational.
This becomes a contradiction of our assumption.
Hence 5+3√2 is irrational number
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