Question

Given that √2 is irrational. Probe that(5+3√2) is an irrational number​

Answer 1

Answer:

5+3√2=a/b

3√2=a/b-5

3√2=a-5b/b

√2=a-5b/b×1/3

√2=a-5b/3b

a and b are integers a-5b/3b is rational and so √2 is rational

But this contradicts the fact that √2 is an irrational

So we conclude that 5+3√2 is an irrational