given that √2 is irrational,prove that (5+3√2) is an irrational number
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Heya☺
Let 5+3√2 be a rational no. then 5+3√2 = P/q where P and q are integers and co-prime numbers and q is not equal to 0
5+3√2 = P/q
√2 =( P/q -5)× 1/3
Here P/q , -5 , 1/3 are all integers and hence rational no.too this means √2 is also a rational no.
But this contradicts with the fact that √2 is an irrational no.
Hence our supposition was wrong
5+3√2 is an irrational no.
Hence proved
✌✌Hope this helps u❕
Let 5+3√2 be a rational no. then 5+3√2 = P/q where P and q are integers and co-prime numbers and q is not equal to 0
5+3√2 = P/q
√2 =( P/q -5)× 1/3
Here P/q , -5 , 1/3 are all integers and hence rational no.too this means √2 is also a rational no.
But this contradicts with the fact that √2 is an irrational no.
Hence our supposition was wrong
5+3√2 is an irrational no.
Hence proved
✌✌Hope this helps u❕
Ramayadav:
thanks for your help
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