Given that √2 is irrational, prove that (5+3√2) is an irrational number.
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Hey Mate..!!
Here's Your Answer..!!
Given: √2 is irrational.
To Prove: 5+3√2 is irrational.
Let us just assume that 5+3√2 is rational.
As we know that rational numbers are in the form of p/q.
So, if 5+3√2 is rational (as we have assumed) it must be in p/q form where q≠0.
Then,
5+3√2 = p/q
3√2 = p/q-5
3√2 = p-5q/q
√2 = p-5q/3q
We know that, √2 is irrational and
p-5q/3q is rational.
And, Rational≠Irrational
Therefore, 5+3√2 is irrational.
Hence Proved.
Hope This Helps..!!
#BeBrainly❤️
Here's Your Answer..!!
Given: √2 is irrational.
To Prove: 5+3√2 is irrational.
Let us just assume that 5+3√2 is rational.
As we know that rational numbers are in the form of p/q.
So, if 5+3√2 is rational (as we have assumed) it must be in p/q form where q≠0.
Then,
5+3√2 = p/q
3√2 = p/q-5
3√2 = p-5q/q
√2 = p-5q/3q
We know that, √2 is irrational and
p-5q/3q is rational.
And, Rational≠Irrational
Therefore, 5+3√2 is irrational.
Hence Proved.
Hope This Helps..!!
#BeBrainly❤️
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