Question

given that 2y^2-x^3=0 and y>0, find dy/dx

Answer 1

Answer:

dy/dx=3√(2x)

Step-by-step explanation:

Answer is,

=4y.dy/dx-3x^2=0

=dy/dx=3x^2/4y

=dy/dx=3√2x/√x,[y=√(x^3/2)]

=dy/dx=3√(2x)