given that ✓3 is a zero of the polynomial x3+ x2-3x-3,find its other two zeros
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Using Synthetic Division, the other two zeroes are (-√3) and (-1).
-WonderGirl
-WonderGirl
Answered by
1
same model
6x³ + √2x² -10x -4√2
= 6x³ -6√2x² + 7√2x² -14x + 4x - 4√2
= 6x²(x - √2) + 7√2x(x -2) + 4(x -√2)
= {6x² + 7√2x + 4}(x - √2)
= {6x² + 3√2x + 4√2x + 4}(x -√2)
= {3√2x(√2x + 1) + 4(√2x +1)}(x -√2)
= (3√2x +4)(√2x +1)(x - √2)
6x³ + √2x² -10x -4√2
= 6x³ -6√2x² + 7√2x² -14x + 4x - 4√2
= 6x²(x - √2) + 7√2x(x -2) + 4(x -√2)
= {6x² + 7√2x + 4}(x - √2)
= {6x² + 3√2x + 4√2x + 4}(x -√2)
= {3√2x(√2x + 1) + 4(√2x +1)}(x -√2)
= (3√2x +4)(√2x +1)(x - √2)
harnamsingh1:
ver ok a na
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