Given that 3 x minus 4 Y is equal to 7 and X + C Y is equal to 13 then for what value of C will the two equation have not have a solution
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Answer:
for no solution we must have a1/a2=b1/b2 not equal to c1/c2
Step-by-step explanation:
3x-4y=7 x+cy=13
a1= 3
a2=1
b1= -4
b2= c
c1=7
c2=13
3/1=-4/cnot equal to 7/13
3c=-4
c=-4/3
And 7c us not equal to -52
so c is not equal to -52/7
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