Question

given that (3x-1)(x+p)=3x^2+qp-2
find the value of
p
q

Answer 1

Your question might be : (3x-1)(x+p)=3x^2+qx-2

Find the value of p,q

Answer:

p = 2

q = 5

Step-by-step explanation:

$=(3x-1)(x+p) \\ =3x(x+p)-1(x+p)\\= 3x^2+3xp-x-p\\= 3x^2+(3p-1)x-p \\=3x^2+qx-2$

Now compare the last two,

p = 2

q = 3p-1

q = 3(2) - 1

q = 6 - 1

q = 5