Question

Given that 3x+4y=26
(I). Express x in terms of y and thus find x when y=5
(ii). Express y in terms of x and thus find y when x =10

Answer 1

Answer:

ANSWER

Given, equation: $$3x - 2y = 6$$.

Now, to check whether (1,2) will lie on the line 3x−2y=6, we have to put the value of (x,y) in the given equation.

LHS =3(1)−2(2)=3−4=−1

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=6 or RHS

Therefore, the point (1,2) will not lie on the line 3x−2y=6.

Now, at x=4, we have,

3(4)−2y=6

y=3

Again, 3x−2y=6

⇒ At x=0,y=−3 and at y=0,x=2

Therefore, table of points is:

x 0 2

y −3 0

So, graph of the given line is as:

solution

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

(l). y = 5

then 3x + 4(5) = 26

3x + 20 = 26

x = 26-20/3

x = 6/3

x =2

(ii). x = 10

then

3(10)+4y=26

30 +4y. = 26

4y =. 26-30

y = -4/4

y= -1

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