given that 4 is a perfect square find the largest possibile value of x
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Greatest number of 4 digits =9999.
We find 9999 by long division method.
The remainder is 198.
This shows 992 is less than 9999 by 198.
This means, if we subtract the remainder from the number we get a perfect square.
Therefore the required perfects square is 9999−198=9801.
And 9801=99
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