Given that 45 is the difference between a number and that formed by reversing its digits. If the sum of the digits of the number is 13, then find the no. if you give me the method along with the answer then i will mark you as brainliest
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Let the unit digit be x then the tens digit will be (13 - x).
Accordind to the condition in the question, we get
[10(13 - x) + x] - (10x + 13 - x) = 45
→ 130 - 10x + x - 9x - 13 = 45
→ -18x = - 72
→ x = 4
Two digit number = 10(13 - x) + x = 10(13 - 4) + 4 = 94
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Answer:
94 is answer dear friend
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