Question

Given that 45 is the difference between a number and that formed by reversing its digits. If the sum of digits of the number is 13,find the number​

Answer 1

$\huge\red{Answer}$

Let the unit digit be x then the tens digit will be (13 - x).

Accordind to the condition in the question, we get

[10(13 - x) + x] - (10x + 13 - x) = 45

→ 130 - 10x + x - 9x - 13 = 45

→ -18x = - 72

→ x = 4

Two digit number = 10(13 - x) + x

= 10(13 - 4) + 4

= 94

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