given that 5A - 3 = 216 and ab equals to 15 find the value of 25 square + 9 b square PLZ... SOMEONE GIVE THE ANSWER
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Answered by
3
Answer:
(5a -3b)^2=16^2
( {x - y})^{2} = {x}^{2} + {y}^{2} - 2xy(x−y)
2
=x
2
+y
2
−2xy
(5a)^2+ (3b)^2 -2*5a*3b=256
25a^2+9b^2-2(15)=256(adding value of ab)
25a^2+9b^2-30=256
25a^2+9b^2=256-30
25a^2+9b^2=226
Answered by
0
Explanation:
5a -3b)^2=16^2
( {x - y})^{2} = {x}^{2} + {y}^{2} - 2xy(x−y)
2
=x
2
+y
2
−2xy
(5a)^2+ (3b)^2 -2*5a*3b=256
25a^2+9b^2-2(15)=256(adding value of ab)
25a^2+9b^2-30=256
25a^2+9b^2=256-30
25a^2+9b^2=226
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