Question

Given that 5sinA=3,find sec square A-tan square A??​

Answer 1

I hope you are satisfied by my answer.

Answer 2

Answer:

1

Step-by-step explanation:

5sinA = 3

sinA = 3/5

Therefore the triangle will be a right angled 3,4,5 triangle where opposite side = 3units ; adjacent = 4 units and hypotenuse = 5 units

sec square A = (hypotenuse / adjacent) whole square  = 25/16

tan square A = (opposite/adjacent)whole square = 9/16

sec square A-tan square A =  25/16 - 9/16 = 1

OR

There is a property that sec^2 θ - tan^2θ  = 1 for any value of θ