Given that [ 6 −2 2 3 ] x = ( 10 −4 ), state the order of x. Also find x.
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Here, AX=B, where A=[
2
(i) The order of A is 2×2 and order of B is 2×1. Let the order of X be m×n.
Now, AX will exist only if the number of columns of A is equal to the number of rows of X, i.e, m=2
When a matrix of order a×c is multiplied with another matrix of order c×b, the resultant matrix has the order a×b.
Therefore, order of matrix X is 2
Therefore,
2a+b=7...(1)
−3a+4b=6...(2)
From (1), we get b=7−2a. Substitute this value of in (2).
−3a+4(7−2a)=6
⇒−3a+28−8a=6⇒11a=22⇒a=2
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