Given that 7(8^n_1) =448 find n
Answers
Answered by
1
Step-by-step explanation:
Divide both sides by -7 so as to isolate the
n
2
term.
−
7
1
n
2
−
7
1
=
−
448
64
−
7
1
⇒
n
2
=
64
now take the square root of both sides
√
n
2
=
±
√
64
⇒
n
=
±
8
Answered by
1
Answer:
n=2-1
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Step-by-step explanation:
7(8
n+1
)=448
Use the rules of exponents and logarithms to solve the equation.
7×8
n+1
=448
Divide both sides by 7.
8
n+1
=64
Take the logarithm of both sides of the equation.
log(8
n+1
)=log(64)
The logarithm of a number raised to a power is the power times the logarithm of the number.
(n+1)log(8)=log(64)
Divide both sides by log(8).
n+1=
log(8)
log(64)
By the change-of-base formula
log(b)
log(a)
=log
b
(a).
n+1=log
8
(64)
Subtract 1 from both sides of the equation.
n=2−1
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