Given that A = 3i+] + 2k and B = 1 - 2j-4k are the position vectors of points P and
(a) Find an equation for the plane passing through Q and perpendicular to line PQ.
(6) What is the distance from the point (-1,1,1) to the plane ?
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Answer:
The equation of plane is (r−β).(α−β)=0
⇒2x−y+6z+24=0
Therefore, perpendicular distance from (−1,1,1) is d=∣∣∣∣∣4+1+36−2−1+6+24∣∣∣∣∣=4127
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