Question

given that a→=4iˆ+3jˆ+kˆ and b→=-i^+jˆ+4kˆ .find the c such that a-b+c=0​

Answer 1

Answer:

When vector is perpendicualr dot product is zero

(2

i

^

+3

j

^

+8

k

^

).(4

j

^

−4

i

^

+α

k

^

)=0

−8+12+8α=0

8α=−4

So, α=

2

−1

α=

2

1

(2i^+3j^+8k^).(4j^−4i^+αk^)=0

Answer 2

Answer:

a+b+c=0

4i^+3j^+k^-i^+j^+4k^+c=0.....(2)

3i^+4j^+5k^+c=0

c=-(3i^+5k^+c^)

Explanation:

take i^,j^and k^ common in step2

Thanks