Question

Given that (a-b)² = 24 and ab =5, find the value of 2a² + 2b² .

Answer 1

Answer:

Let me help you for this question.....

We are given : $(a-b)^{2}$ = 24 and ab = 5

So at first first let us multiply 4 on both sides in the equation ab = 5

=> 4ab = 20

Now, we need to find $2a^{2} + 2b^{2}$ or  $2(a^{2} + b^{2} )$

=> We can write $2(a^{2} + b^{2} ) = 2(a-b)^{2} - 4ab$ ( Expand (a-b)^2 you'll get 2a^2 + 2b^2 only)

=> $2a^{2}+2b^{2}$ = 2(24) - 20

SO finally you'll get the answer as 28

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