Given that |⃗a ×b ⃗ | = √3 ⃗ a.⃗b then what is the angle between ⃗ aand ⃗⃗ b?
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Angle between A and B is 60° or π/3 rad
Explanation:
We know that
|A × B| = ABsinФ
A·B = ABcosФ
Therefore,
|⃗A ×B ⃗ | = √3 ⃗ A.⃗B
ABsinФ = √3 ABcosФ
sinФ = √3 cosФ
sinФ/cosФ = √3
tanФ = √3
Ф = 60° or π/3 rad
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