Given that a,b,c,and d are natural numbers and that a=bcd, b = cda, d = abc then ( a + b + c + d) ^2 is
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let ..a.b.c and d =1
:. (a+b+c+d)^2
=(1+1+1+1)^2=16
:. (a+b+c+d)^2
=(1+1+1+1)^2=16
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