Question

Given that A = B+C , prove that

tan A- tan B- tan C = tan A tan B tan C​​

Answer 1

Answer:

ANSWER

⇒ A=B+C

Multiplying tan on both sides,

⇒ tan(B+C)=tanA

⇒ tanB+tanC =tanA

1-tanB tanC

=

⇒ tanB+tanC=tanA(1−tanB tanC)

⇒ tanB+tanC=tanA−tanB tanA tanC

⇒ tanB tanA tanC=tanB−tanC−tanA

=tanB

⇒ tanA+tanC=tanB(1−tanA tanC)

⇒ tanA+tanC=tanB−tanA tanB tanC

⇒ tanAtanBtanC=tanB−tanC−tanA

[❤✔]✌

Answer 2

Answer:

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Step-by-step explanation:

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