Given that A= B+C, prove that Tan A -tan B- tanC =tanAtanBtanC
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To prove -
If A = B+C then
tanA - tanB - tanC = tanA.tanB.tanC.
Proof -
Clearly
A = B+C
tanA = tan( B+C)
We know that
tan( a + b) =( tan a+ tan b) /1- tan a .tan b
So,
→tan A =( tan B+ tan C)/ 1 - tanB. tanC
→tanA( 1 - tanB tanC) = tanB +tanC
→tanA - tanA tanB tanC = tan B + tan C
→tanA - tanB - tanC = tanA.tanB.tanC
Hence proved .
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