given that A=B+C, prove that tanA-tanB-tanC= tanA tanB tanC
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Answer:
take sum of ABC equals to 180 and then solve
Step-by-step explanation:
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To prove:
If A=B+C, prove that tanA-tanB-tanC= tanA tanB tanC
Proof:
A = B+C
tanA = tan(B+C)
tanA = (tanB+tanC)/1-tanBtanC
tanA(1-tanBtanC) = tanB+tanC
tanA - tanAtanBtanC = tanB+tanC
tanA - tanB - tanC = tanAtanBtanC
Hence the proof
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