Given that A+B=R and A+2B is perpendicular to A. Then
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Given
Given that A+B=R and A+2 B is perpendicular to A. Then relation between b and r.
Given a + 2 b is perpendicular to a
By property of vector dot product between a + 2 b and a is equal to 0.
Therefore (a + 2 b).a = 0
Now a^2 + 2 ab = 0
But a + b = r
a = r – b
So (r – b)^2 + 2b(r – b) = 0
r ^2 – 2 r b + b^2 + 2b.r – 2b^2 = 0
r^2 – b^2 = 0
(r – b)(r + b) = 0
So r = ± b
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