given that a body falling freely passes through 5390 in the sixth second.find the value of g
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Explanation:
Here,
s=5390cm =( 5390/100)m
u=0
t=6
Using
S=ut+1/2at^2
53.90= 0t +1/2(6^2)a
= 18a
a = 53.90/18 = g
g = 2.9944444 or 3m/s^2 or
299.44cm/s^2
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