Question

given that a body falling freely passes through 5390 in the sixth second.find the value of g​

Answer 1

Explanation:

Here,

s=5390cm =( 5390/100)m

u=0

t=6

Using

S=ut+1/2at^2

53.90= 0t +1/2(6^2)a

= 18a

a = 53.90/18 = g

g = 2.9944444 or 3m/s^2 or

299.44cm/s^2