Question

given that a communication satellite of 2400kg is placed in a geostationary orbit at a distance of 4.23×10^7m from the centre of the health , calculate a.the angular velocity of the satellite b. the speed of the satellite c. the acceleration of the satellite and d. the force of attraction between the earth and the satellite .....take G=6.6×10^_11 M= 6.0×10^24kg and g=9.80m/s2 ​

Answer 1

ggk hgj tu kdueuuryt hu ki baba ki jai ho gaya hai agar nahi hai agar nahi