Question

Given that a function is defined by f(x)=2x-3,evaluatef(1)

Answer 1

Answer:

-1

Step-by-step explanation:

f(x)=2x-3

f(1)=2(1)-3

f(1)=2-3

f(1)= -1

Answer 2

Answer:

The function value is f(0)+f(1)\div 2=-3.5f(0)+f(1)÷2=−3.5

Step-by-step explanation:

Given : A function f is defined by f(x)=2x-3f(x)=2x−3

To find : Expression f(0)+f(1)\div 2f(0)+f(1)÷2 ?

Solution :

Function f(x)=2x-3f(x)=2x−3

Put x=0,

f(0)=2(0)-3f(0)=2(0)−3

f(0)=-3f(0)=−3

Put x=1,

f(1)=2(1)-3f(1)=2(1)−3

f(1)=-1f(1)=−1

Substitute in the expression,

f(0)+f(1)\div 2=-3+(-1)\div 2f(0)+f(1)÷2=−3+(−1)÷2

f(0)+f(1)\div 2=-3-\frac{1}{2}f(0)+f(1)÷2=−3−

2

1

f(0)+f(1)\div 2=\frac{-6-1}{2}f(0)+f(1)÷2=

2

−6−1

f(0)+f(1)\div 2=\frac{-7}{2}f(0)+f(1)÷2=

2

−7

f(0)+f(1)\div 2=-3.5f(0)+f(1)÷2=−3.5

Therefore, the function value is f(0)+f(1)\div 2=-3.5f(0)+f(1)÷2=−3.5

#Learn more

Brainly what function is represented below? f(x) = f(x) = + 2 f(x) = f(x) = − 2

Step-by-step explanation:

make me as brainliest