Given that a=i-j/√2 show that |a|=1
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Answer:
very easy
Step-by-step explanation:
Given,
a=(i-j)/√2 = (1/√2)i-(1/√2)j
Now,
|a| = √{(1/√2)²+(-1/√2)²} = √{1/2+1/2} = √1 = 1.
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