Question

Given that a square +a square b=320 find the value of b when a=8

Answer 1

a^2+b^2= 320

a^2+ 64 = 320

a^2=320-64

a^2=256

a=√256

a= 16

Answer 2

Answer:

b=4

Step-by-step explanation:

We have given the equation that $a^{2}+a^{2}b=320$ and $a=8$

Now putting value of a in the given equation we can find the value of b from this equation

$8^{2}+8^{2}b=320$

=$64+64b=320$

=$64b=256$

Hence the final answer will be

$b=4$